mistyboy
contestada

A 2,000-kg car traveling at 40 m/s hits a wall with a force of 40,000 N and comes to a stop. What was the impact time?

Respuesta :

If I did my math correct, the answer would be 2 seconds.

Answer:

The impact time is equal to [tex]2[/tex] seconds

Explanation:

Given -

Force (F) [tex]= 40,000[/tex] N or [tex]\frac{Kg-m}{s^2}[/tex]

Mass(M) [tex]= 2,000[/tex] Kg

Initial Velocity (u) [tex]= 40\frac{m}{s}[/tex]

Final Velocity (v) [tex]= 0\frac{m}{s}[/tex]

Force exerted by any body is equal to the product of its mass and acceleration

Hence, mathematically it can be represented as

[tex]F = M * a[/tex]

Substituting the given values, we get -

[tex]40,000 = 2,000 * a\\a = 20 \frac{m}{s^2}[/tex]

As per Newton's first law of motion,

[tex]v = u - at[/tex] in case of deceleration

Substituting the available values in above equation, we get -

[tex]0 = 40 - 20 * t\\40 = 20*t\\t = \frac{40}{20} \\t = 2[/tex] seconds

The impact time is equal to [tex]2[/tex] seconds

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