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In the figure, OA = r and OC = R. The sector COB is cut from the circle with center O. The ratio of the area of the sector removed from the outer circle to the area of the sector removed from the inner circle is

Respuesta :

DeanR

We don't have to stress too much over the details, which are a little muddled here. When we scale the linear dimension by a factor of f we scale areas by a factor of [tex]f^2[/tex].


It's not totally clear from the question but let's say A is on the inner circle of radius r and B on the outer circle of radius R. The linear dimensions are scaled by the ratio [tex]R/r[/tex] so the area is scaled by


Answer: [tex] \dfrac{R^2}{r^2} [/tex]



Answer:

R^2/r^2

Step-by-step explanation:

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