Respuesta :
As, 5 mL water is required for 1 g kanamycin and thus for 700 mg capsule or 0.7 g capsule, the amount of solvent required is:
for 700 mg capsule = 5 * 0.7 mL = 3.5 mL
hence, 3.5 mL solvent is required.
Answer:3.5 ml of water will be required to sterile the 700 mg of Kanamycin.
Explanation:
Mass of te Kamamycin = 700 mg = 0.7 g
1000 mg = 1 g
1 grams of Kanamycin is sterile by 5 mL of water as stated in label
Then ,0.7 g of water will be sterile by =[tex] 0.7 g\times 5ml=3.5 mL[/tex]
3.5 ml of water will be required to sterile the 700 mg of Kanamycin.
