The bicycle traveled about 22 m during the 5.0 seconds of braking
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Further explanation
Centripetal Acceleration can be formulated as follows:
[tex]\large {\boxed {a = \frac{ v^2 } { R } }[/tex]
a = Centripetal Acceleration ( m/s² )
v = Tangential Speed of Particle ( m/s )
R = Radius of Circular Motion ( m )
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Centripetal Force can be formulated as follows:
[tex]\large {\boxed {F = m \frac{ v^2 } { R } }[/tex]
F = Centripetal Force ( m/s² )
m = mass of Particle ( kg )
v = Tangential Speed of Particle ( m/s )
R = Radius of Circular Motion ( m )
Let us now tackle the problem !
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Given:
radius of wheel = R = 0.70 m
initial angular speed = ω = 2.0 rev/s = 4π rad/s
final angular speed = ωo = 0 rad/s
time taken = t = 5.0 s
Asked:
distance covered = d = ?
Solution:
[tex]d = \theta R[/tex]
[tex]d = (\omega + \omega_o)\frac{1}{2}t R[/tex]
[tex]d = ( 4 \pi + 0 ) \frac{1}{2}(5.0)( 0.70 )[/tex]
[tex]d = 4\pi (1.75)[/tex]
[tex]d = 7\pi \texttt{ m}[/tex]
[tex]d \approx 22 \texttt{ m}[/tex]
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Learn more
- Impacts of Gravity : https://brainly.com/question/5330244
- Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454
- The Acceleration Due To Gravity : https://brainly.com/question/4189441
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Answer details
Grade: High School
Subject: Physics
Chapter: Circular Motion
