Respuesta :
Gravitational force is given by, [tex] F= G\frac{mM}{R^{2}} [/tex]
Where, m and M are the masses of the objects, R is the distance between them and G gravitational constant.
Gravitational force of the star on planet 1, [tex] F_{1}= G\frac{m_{1}M}{R^{2}} [/tex]
Gravitational force of the star on planet 2, [tex] F_{2}= G\frac{3m_{1}M}{(3R)^{2}} [/tex]
Ratio, [tex] \frac{F_{1}}{F_{2}}= \frac{\frac{Gm_{1}M}{R^{2}}}{\frac{G3m_{1}M}{(3R)^{2}}} [/tex]
[tex] \frac{F_{1}}{F_{2}}= \frac{3}{1} [/tex]
Therefore, the gravitational force of the star on the planet 1 is three times that on planet 2.
The ratio of gravitational forces F₂ : F₁ = 1 : 3
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Further explanation
Newton's gravitational law states that the force of attraction between two objects can be formulated as follows:
[tex]\large {\boxed {F = G \frac{m_1 ~ m_2}{R^2}} }[/tex]
F = Gravitational Force ( Newton )
G = Gravitational Constant ( 6.67 × 10⁻¹¹ Nm² / kg² )
m = Object's Mass ( kg )
R = Distance Between Objects ( m )
Let us now tackle the problem !
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Given:
Gravitational force on planet 1 = F₁
Gravitational force on planet 2 = F₂
mass of planet 1 = m₁
mass of planet 2 = m₂ = 3m₁
distance between planet 1 and star = R₁
distance between planet 2 and star = R₂ = 3R₁
Asked:
ratio of force = F₂ : F₁ = ?
Solution:
[tex]F_2 : F_1 = G \frac{ M m_2} { (R_2)^2 } : G \frac{ M m_1} { (R_1)^2 }[/tex]
[tex]F_2 : F_1 = \frac{m_2} { (R_2)^2 } : \frac{ m_1} { (R_1)^2 }[/tex]
[tex]F_2 : F_1 = \frac{3m_1} { (3R_1)^2 } : \frac{ m_1} { (R_1)^2 }[/tex]
[tex]F_2 : F_1 = \frac{3} { 9 } : 1[/tex]
[tex]F_2 : F_1 = \frac{1} { 3 } : 1[/tex]
[tex]\boxed{F_2 : F_1 = 1 : 3}[/tex]
[tex]\texttt{ }[/tex]
Learn more
- Impacts of Gravity : https://brainly.com/question/5330244
- Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454
- The Acceleration Due To Gravity : https://brainly.com/question/4189441
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Answer details
Grade: High School
Subject: Physics
Chapter: Gravitational Fields
