Torque on the wheel produced by the chain is given by,
τ= F×R= FRsin∅
here, R is the radius of the wheel = 7.70 cm=0.077 m
∅= angle between the action of force and point of contact = 90°(angle between wheel and the chain)
Substituting the values,
τ=[tex] 35.0*0.077*sin90° [/tex]
= 2.6 N
It is the force exerted by the chain on the wheel. Therefore, a torque of 2.6 N would be needed to stop the wheel form turning.
Answer:
Torque, [tex]\tau=2.69\ N-m[/tex]
Explanation:
It is given that,
Radius of the wheel, r = 7.7 cm = 0.077 m
Force exerted on the wheel, F = 35 N
To find,
Torque needed to keep the wheel from turning.
Solution,
We know that the product of force and distance is called torque. It is given by :
[tex]\tau=r\times F[/tex]
[tex]\tau=0.077\ m\times 35\ N[/tex]
[tex]\tau=2.69\ N-m[/tex]
So, the torque needed to keep the wheel from turning is 2.69 N-m.
