Option (c) is correct.
Explanation:
initial velocity along vertical=0
velocity along horizontal Vx=40.20 m/s
acceleration along the vertical=9.8 m/s²
displacement along vertical,h=2 m
using the kinematic equation
h= vi*t + 1/2 g t²
2=0(t) + 1/2 (9.8)t²
t²=0.408
t=0.639 s
now the displacement along vertical= x= Vx* t
x=40.20 (0.639)
x=25.73 m
