well, we can check the units right off the grid.
so, below the x-axis, we have a rectangle, is a 10x3, so it has an area of 10*3.
above the x-axis we have a trapezoid, it has to parallel sides or bases, top is 6 units, bottom base is 10 units, and it has an altitude of 2.
we can just get the area of both, sum them up, and that's the area of the figure.
[tex]\bf \textit{area of a trapezoid}\\\\
A=\cfrac{h(a+b)}{2}~~
\begin{cases}
a,b=\stackrel{bases}{parallel~sides}\\
h=height
\end{cases}\\\\
-------------------------------\\\\
\stackrel{rectangle}{(10\cdot 3)}~~+~~\stackrel{trapezoid}{\cfrac{h(a+b)}{2}}\implies \stackrel{rectangle}{(10\cdot 3)}~~+~~\stackrel{trapezoid}{\cfrac{2(6+10)}{2}}
\\\\\\
30+16\implies 46[/tex]
