Suppose you invest 1,600 at an annual interest rate of 7.9% compounded continuously. How much will you have in the account after 10 years

Respuesta :

[tex] \bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount}
\\\\
A=Pe^{rt}\qquad
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$1600\\
r=rate\to 7.9\%\to \frac{7.9}{100}\to &0.079\\
t=years\to &10
\end{cases}
\\\\\\
A=1600e^{0.079\cdot 10}\implies A=1600e^{0.79}\implies A\approx 3525.434 [/tex]

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