Which of the following are solutions to the equation sinx cosx = (sqrt of 3)/4? Check all that apply.

A. (pi/6)+npi
B. (pi/12)+npi
C. (2pi/6)+npi
D. (pi/12)+(npi)/2

Respuesta :

DeanR

[tex] \sin x \cos x = \dfrac{\sqrt 3}{4}[/tex]


[tex] 2 \sin x \cos x = \dfrac{\sqrt 3}{2}[/tex]


[tex]\sin 2x = \sin \frac \pi 3[/tex]


[tex] 2x = \frac \pi 3 + 2 \pi n \textrm{ or } 2x = (\pi - \frac \pi 3) + 2 \pi n \quad \textrm{integer } n[/tex]


[tex] x = \frac \pi 6 + \pi n \textrm{ or } x = \frac \pi 3 + \pi n[/tex]


Choices A and C



Answer:

he/she is right that's the answer

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