First of all, let's fill the gaps. The z score for 184 is -0.62.22. The percent associated with this is 62.22%. The z score for 200 is -0.622.22. The percent associated with this is 48.6%. The percent of the expenses is 622.22
We have to apply z-score formula in order to solve this problem. The formula is
z = (x-u) / s
Plugging z-scores at 184 and 200, we find
[tex] z_{1} = \frac{184-206}{10} = -2.20 [/tex]
The corresponding probability with this number is P(1) = 0.9861
[tex] z_{2} = \frac{200-206}{10} = -0.60 [/tex]
The corresponding probability with this number is P(2) = 0.7257
Probability between 184 and 200 is P(1) - P(2) = 0.2604