a. Total number of candies = 100
Red = 21, Blue= 22, Yellow= 19 and Brown= 38
Let, A is the event of selecting Blue candy
So, n(A) = 22
Total possible outcome, n(S)= 100
So, P(A) = [tex] \frac{n(A)}{n(S)} [/tex]
P(A) = [tex] \frac{22}{100} [/tex]
P(A) = 0.22 = 22%
So, the probability of selecting one candy which is blue = 22%
b. As the maker of the candy claims that 24% of its candies are blue and 22% is close to 24%, so the estimate in part(a) roughly agree with the claim.
