The molecular mass of [tex]H_2SO_4[/tex] is:
2·1 + 1·32 + 4·16 = 98 g/mol
The amount of solute, expressed by mol, is:
[tex]73.5\ g\ H_2SO_4\cdot \frac{1\ mol}{98\ g} = 0.75\ mol\ H_2SO_4[/tex]
The molar concentration definition is: [tex]M = \frac{mol\ solute}{volume (L)\ solution}[/tex]
Doing the calculations:
[tex]M = \frac{0.75\ mol}{3\ L} = \bf 0.25\ M[/tex]
(If you detect any mistakes in my English report me them, please).
Answer:
0.25
Moles of solute = (Liters of solution) x (molarity of solution)
Moles of solute = (Kg of solution) x (molality of solution)
