The Pyhtagorean triple for a 45-45-90 is [tex] (x,x,x\sqrt{2}) [/tex]
with the last measure being that of the hypotenuse since it is the longest. If the hypotenuse is given as
[tex] 22\sqrt{2} [/tex]
then in equality form we could rewrite as [tex] 22\sqrt{2}=x\sqrt{2} [/tex]. We would divide both sides by the square root of 2 and solve for x, the length of each leg of that triangle. Each leg measures 22.
