m = mass of sample = 15.6 g = 0.0156 kg
c = specific heat of the sample = 0.58 kcal/kgC = 580 cal/(kgC)
[tex] T_{i} [/tex] = initial temperature = 21.5 C
[tex] T_{f} [/tex] = final temperature = ?
Q = heat absorbed = 0.207 kcal = 207 cal
using the equation
Q = m c ([tex] T_{f} [/tex]-[tex] T_{i} [/tex])
207 = (0.0156) (580) ([tex] T_{f} [/tex]-21.5)
[tex] T_{f} [/tex] = 44.4
