Here [tex] f(x) =2-\sqrt{x} [/tex]
[tex] g(x)=x^{2} -9 [/tex]
[tex] g(x)-f(x) = x^{2} -9-2- \sqrt{x} [/tex]
[tex] g(x)-f(x) =x^{2} -11-\sqrt{x} [/tex]
For a radical square-root function, there cannot be a negative number inside the radical. Thus, to find the domain of a radical square root function, we set up the value inside the radical as an inequality greater than or equal to 0 and solve the inequality for the variable.
So domain here would be ≥≥≥[tex] x\geq 0 [/tex]
