413 g of Ag are in 2.30 x 10^24 atoms in silver.
From Avogadro's law, we know that the number of elementary entities in one mole of a substance is given by the Avogadro's number, 6.02 × 10^23 atoms.
In this case, we are told that there are 2.30 x 10^24 atoms in silver. We can find the mass of this number of silver atoms using the Avogadro's number as follows;
1 mole of Ag atoms contain 6.02 × 10^23 atoms
x moles of silver atoms contain 2.30 x 10^24 atoms
x = 1 mole × 2.30 x 10^24 atoms/ 6.02 × 10^23 atoms
x = 3.82 moles of Ag
Mass of 3.82 moles of Ag = 3.82 moles of Ag x 108 g/mol
= 413 g of Ag
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