Hi!
First, we need to find the slope.
Here's the equation to find the slope.
[tex] \frac{y2-y1}{x2-x1} [/tex]
Put in the values and solve.
[tex] \frac{3-7}{3-(-3)} [/tex]
[tex] -\frac{4}{6} [/tex]
Simplify
[tex] -\frac{2}{3} [/tex]
Now our equation is
[tex] y=-\frac{2}{3}x+b [/tex]
We need to find b. Do this by putting one of the coordinates into the equation then solving.
[tex] 3=-\frac{2}{3}*3+b [/tex]
3=-2-b
5=b
[tex] y=-\frac{2}{3}x+5 [/tex]
The answer is 3) [tex] y=-\frac{2}{3}x+5 [/tex]
Hope this helps! :)
-Peredhel
