how do we solve this ?

I visited Indonesia in 1991 but all I can say now is "saya mau beli mango."
(i) The speed will be the slope of the position versus time graph, so in the first ten seconds that's
[tex] \dfrac{60 \textrm{ meters} - 20 \textrm{ meters}}{10 \textrm{ seconds} - 0 \textrm{ seconds}} =4 \textrm{ meters per second}[/tex]
(ii) The speed is zero when the slope is zero, or flat, horizontal. That's from t=10 seconds to t=20 seconds.
(iii) The last 10 seconds we went from a position of 60 to a position of zero; i.e. we went backwards. That's a speed or slope of
[tex] \dfrac{0 \textrm{ meters} - 60 \textrm{ meters}}{25 \textrm{ seconds} - 20 \textrm{ seconds}} = -12 \textrm{ meters per second}[/tex]
Technically the speed is the absolute value of this velocity, 12 meters per second.
(iv) The average speed is the total change in position over the total time.
[tex] \dfrac{0 \textrm{ meters} - 20 \textrm{ meters}}{25 \textrm{ seconds} - 0 \textrm{ seconds}} = -0.8 \textrm{ meters per second}[/tex]
Again technically the speed is the absolute value of that, 0.8 meters per second.