Answer: The correct answer is [tex]Cl_2+2Br^-\rightarrow Br_2+2Cl^-[/tex]
Explanation:
Net ionic equation is defined as the equation in which total number of electrons exchanged are equal.
We are given two half reactions, out of which one is oxidation half reaction and other is reduction half reaction.
Oxidation half reaction: [tex]2Br^-\rightarrow Br_2+2e^-[/tex]
Reduction half reaction: [tex]Cl_2+2e^-\rightarrow 2Cl^-[/tex]
The net ionic equation for the above reactions will be: [tex]Cl_2+2Br^-\rightarrow Br_2+2Cl^-[/tex]
Hence, the correct answer is [tex]Cl_2+2Br^-\rightarrow Br_2+2Cl^-[/tex]
