Answer:-
399 gram
Explanation:-
The balanced chemical equation for the reaction is
4Fe +3 O2 --> 2 Fe2O3
Atomic mass of Iron Fe is 55.845 gram
Molecular mass of Iron (III) Oxide Fe2O3 is
55.845 x 2 + 16 x 3 = 159.69 gram
From the balanced chemical equation,
4 Fe gives 2 Iron (III) oxide
∴ 4 x 55.845 grams of Fe gives 2 x 159.69 grams of Iron (III) Oxide.
279 grams of Fe gives (2 x 159.69) x 279 / ( 4 x 55.845)
= 399 gram
