Respuesta :

The average kinetic energy of an atom in helium gas at temperature T is given by,

K.E=[tex] \frac{3}{2}KT [/tex]

here, K is botzmann constant =1.38×10⁻²³ m² kg s⁻² K⁻¹

Given, K.E= 6.21×10⁻²¹ J

Substituting the values,

[tex] 6.21*10^{-21}=\frac{3}{2}1.38*10^{-23}T [/tex]

T= 300 K

Therefore, at temperature 300 K the average kinetic energy of the atom in helium gas is 6.21×10⁻²¹ J.

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