Respuesta :

[tex] \dfrac{_7P_6}{_7P_4}=\dfrac{\dfrac{7!}{1!}}{\dfrac{7!}{3!}}=\dfrac{7!}{4\cdot5\cdot6\cdot7}=\dfrac{2\cdot3\cdot4\cdot5\cdot6\cdot7}{4\cdot5\cdot6\cdot7}=2\cdot3=6 [/tex]

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