In this question, we will use combination .
There are 7 male and 7 female representatives . Number of ways of selecting 3 men out of 7 men= 7C3=
[tex] \frac{7!}{3!(7-3)!}
[/tex][tex] =\frac{7*6*5}{3*2} = 35 [/tex]
Number of ways of selecting 3female out of 7 female =7C3=
[tex] \frac{7!}{3!(7-3)!}
[/tex][tex] =\frac{7*6*5}{3*2} = 35 [/tex]
So total number of ways of can the team of 6 be selected = 35+35 =70 .
So the final answer is 70 .
