Aluminum has a density of 2.7 g/cm3. If a chunk of aluminum with a mass of 10.8 g is placed in a graduated cylinder partially filled with water, how much will the water level rise?

The water level that will rise is 4 cm^3

calculation

if the density i s 2.7 g/cm^3 this implies that

1cm^3 = 2.7 g
? = 10.8 g

by cross multiplication

(1 cm^3 x 10. 8 g) /2.7 g = 4 CM^3

Answer Link

david8644 david8644 · Answer 2 · 2019-09-19T01:07:39+02:00

Answer:

[tex]4 cm^{3}[/tex]

Explanation:

As you can see density of aluminium is 2.7 g/cm3 so in order to calculate the volume of a piece of aluminium that is 10.8 g we just ahve to clear the volume from the density formula:

[tex]Density=\frac{mass}{volume} \\Volume=\frac{mass}{density}[/tex]

Now that we have cleared the formula we just have to insert the values:

[tex]Volume=\frac{mass}{density}\\Volume= \frac{10.8}{2.7}\\ Volume= 4 cm^{3}[/tex]

So the volume of the aluminum piece is 4 cm3 so the volume of water displaced would be the same, 4 cm3.