Part 1:
Before we begin, you need to remember the following rule:
[tex] \frac{x^a}{x^b} = x^{a-b} [/tex]
The given expression is:
[tex] \frac{12}{12^3} [/tex]
Since the base is the same in both numerator and denominator, we can apply the above rule. This means that:
[tex] \frac{12}{12^3} [/tex] = 12¹⁻³ = 12⁻²
Part 2:
Before we begin, you need to remember the following rule:
x⁻ᵃ = [tex] \frac{1}{x^a} [/tex]
Now, from part 1, we simplified the expression into 12⁻²
Since the power is negative, we can apply the above rule.
This means that:
12⁻² = [tex] \frac{1}{(12)^2} = \frac{1}{12*12} = \frac{1}{144} [/tex]
Hope this helps :)
