A poster is shown below: what are the dimensions if the poster enlarged by a factor of 7/2
6 in height
18 in length
A: 42 in by 126 in
B: 3 in by 9 in
C: 9 in by 12 in
D: 21 in by 63 in

If the poster is 6 by 18, and it increases by a factor 7/2, then you multiply both the height and length by 7/2:
[tex]6 \times \frac{7}{2} = 21 \\ 18 \times \frac{7}{2} = 63[/tex]
Therefore, the new height is 21, and the new length is 63.

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andromache andromache · Answer 2 · 2022-01-07T12:04:26+01:00

andromache andromache

07-01-2022

The dimensions if the poster enlarged by a factor of 7 by 2 is Option D. 21 in by 63 in.

Given that,

6 in height
18 in length

The calculation is as follows;

[tex]6 \times 7\div 2 = 21\\\\18 \times 7\div 2 = 63[/tex]

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A poster is shown below: what are the dimensions if the poster enlarged by a factor of 7/2 6 in height 18 in length A: 42 in by 126 in B: 3 in by 9 in C: 9 in by 12 in D: 21 in by 63 in

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A poster is shown below: what are the dimensions if the poster enlarged by a factor of 7/2
6 in height
18 in length
A: 42 in by 126 in
B: 3 in by 9 in
C: 9 in by 12 in
D: 21 in by 63 in