The evaluation should be [tex]sec (5\pi\div 4) = -\sqrt{2} [/tex]
We know that
The formula: [tex]sec\ x = 1 \div cos\ x;[/tex]
Now,[tex] sec\ (5\pi\div 4) = 1\div cos (5\pi\div 4);[/tex]
But, [tex]cos (5\pi\div 4) = cos (\pi + \pi\div 4);[/tex]
Now We use the formula[tex]cos (\pi + y) = - cos\ y;[/tex]
So, [tex] cos (\pi + \pi\div 4) = -cos(\pi\div 4) =\sqrt{2} \div -2 [/tex]
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