Respuesta :
[tex]\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------[/tex]
[tex]\bf \textit{area of a rectangle}\\\\ A=WL~~ \begin{cases} W=width\\ L=length\\ -----\\ A=24a^2b\\ L=8ab^2 \end{cases}\implies 24a^2b=W(8ab^2)\implies \cfrac{24a^2b}{8ab^2}=W \\\\\\ \cfrac{24}{8}\cdot \cfrac{a^2b}{ab^2}=W\implies 3\cdot \cfrac{a^2a^{-1}}{b^2b^{-1}}=W\implies 3\cdot \cfrac{a^{2-1}}{b^{2-1}}=W\implies \cfrac{3a}{b}=W[/tex]
[tex]\bf \textit{area of a rectangle}\\\\ A=WL~~ \begin{cases} W=width\\ L=length\\ -----\\ A=24a^2b\\ L=8ab^2 \end{cases}\implies 24a^2b=W(8ab^2)\implies \cfrac{24a^2b}{8ab^2}=W \\\\\\ \cfrac{24}{8}\cdot \cfrac{a^2b}{ab^2}=W\implies 3\cdot \cfrac{a^2a^{-1}}{b^2b^{-1}}=W\implies 3\cdot \cfrac{a^{2-1}}{b^{2-1}}=W\implies \cfrac{3a}{b}=W[/tex]
