Respuesta :
The balanced equation is:
[tex]2Na_3N-\ \textgreater \ 6Na + N_2[/tex]
Then proceed with the following equations.
[tex]100g Na_3N*(\frac{1molNa_3N}{82.98gNa_3N})*(\frac {6mol Na}{2molNa_3N})*(\frac {22.99gNa}{1molNa})=83.12gNa[/tex]
The answer is [tex]83.12gNa[/tex].
[tex]2Na_3N-\ \textgreater \ 6Na + N_2[/tex]
Then proceed with the following equations.
[tex]100g Na_3N*(\frac{1molNa_3N}{82.98gNa_3N})*(\frac {6mol Na}{2molNa_3N})*(\frac {22.99gNa}{1molNa})=83.12gNa[/tex]
The answer is [tex]83.12gNa[/tex].
Answer:
3.62 moles
Explanation:
Sodium nitride (Na₃N) will decompose as shown in the balanced equation below
2Na₃N → 6Na + N₂
The molar mass of sodium nitride in the solution is
Mass of Na above is (2 ₓ 3 ₓ 23) = 138 g
Mass of N above is (2 ₓ 14) = 28 g
Mass of Na₃N = 138g + 28g = 166g
From the equation above, we can deduce that 166g of Na₃N will produce 6 moles of sodium. Hence 100g of Na₃N will produce X moles of sodium where X is unknown.
∴ 166g of Na₃N → 6 moles of Na
100g of Na₃N → X moles of Na
When the above is cross multiplied,
X = [tex]\frac{100 * 6}{166}[/tex]
X = 3.62 moles
3.62 moles of sodium (Na) will be formed when 100g of Na₃N decomposes