Two people are standing on opposite sides of a hill. Person A makes an angle of elevation of 65° with the top of the hill and person B makes an angle of elevation of 80° with the top of the hill. The two people are standing 45 feet from each other. What is the distance from person B to the top of the hill?

see the picture to better understand the problem

we know that
in the triangle ABC
∠A+∠B+∠C=180°
find ∠C
∠C=180-[80+65]------> ∠C=35°

Applying the law of sines

AB/sin C=CB/sin A
solve for CB
CB=AB*sin A/sin C-----> CB=45*sin 65/sin 35-----> CB=71.10 ft

the answer is
the distance from person B to the top of the hill is 71.10 feet

Answer Link

david8644 david8644 · Answer 2 · 2019-07-05T21:56:32+02:00

Answer:

71.10 feet

Step-by-step explanation:

To solve this you have to remember the laws of the triangles and the law of sines, this states that every triangle´s sum of the inner angles are 180º

This means that if angle A is 65º and angle B is 80º angle C which would be the angle created on the top oof the mountain byt the lines that conect the top of the mountain with person A and B would be 35º.

Now the law of sines goes like this:

[tex]\frac{A}{Sine angle A}=\frac{B}{Sine angle B}=\frac{C}{Sine angle C}[/tex]

If you put the values of the different angles you´d get:

[tex]\frac{x}{sine 65}=\frac{45}{sine 35}[/tex]

When you clear the equation it will end up like this:

x= [tex]\frac{(sine 65)(45)}{sine 35}[/tex]

x= 71.1