Answer:
91.728 cal required to increase the temperature 11 °C to 23 °C.
Explanation:
Mass of the alcohol ,m= 13 g
The specific heat of the alcohol,c = 0.588 cal/g °C
Change in temperature = [tex]\Delta T=23^oC-11^oc=12^oC[/tex]
Heat required to increase the temperature be Q.
[tex]Q=mc\times \Delta T[/tex]
[tex]Q=13 g\times 0.588 cal/g ^oC\times 12^oC=91.728 cal[/tex]
91.728 cal required to increase the temperature 11 °C to 23 °C.
