Respuesta :

In the given figure the circle with center O has two chords NL and PY OA and OE are the two perpendiculars drawn from the center to the chords. They are at a distance of 3 units from the center or the chords are at equal distance from center

The Theorem states : chords equidistant from the center of a circle are congruent.

The two chords PY and NL are equal.

Option B is the right answer.



From the figure it has been observed that NE is congruent to PY. Option (B) is correct.

Further Explanation:

Given:

The length of OE is [tex]{\text{OE}} = 3{\text{ units}}.[/tex]

The length of OA is [tex]{\text{OA}} = 3{\text{ units}}.[/tex]

Explanation:

The length of OA and OE is [tex]3{\text{ units}}.[/tex]

LI and TG are the chords of the circle.

OE and OA are the perpendicular bisector of the chords LI and TG respectively.

The length of the perpendicular bisector is [tex]3{\text{ units}.[/tex]

The given chords of the circle are equidistant from the center of the circle.

From the figure it has been observed that NE is congruent to PY. Option (B) is correct.

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Answer details:

Grade: High School

Subject: Mathematics

Chapter: Circles

Keywords: congruent, fill, blank, conclude, OE, PY, NL,EL , chord, tangent, displacement, two chords, radius, center, circle, equidistant.

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