Answer:
Work = 2160 J
Explanation:
As per work energy theorem we know that work done is equal to the change in the kinetic energy of the cyclist.
As the cyclist is initially moving at speed 8 m/s and after some time his speed changes to 10 m/s
So here we can say that
final kinetic energy - initial kinetic energy = work done
[tex]W = \frac{1}{2}m(v_f^2 - v_i^2)[/tex]
now by plug in all values
[tex]W = \frac{1}{2}(120)(10^2 - 8^2)[/tex]
[tex]W = 2160 J[/tex]
so work done by cyclist will be 2160 J
