What is the area of this triangle? Enter your answer as a decimal in the box. Round only your final answer to the nearest hundredth. ft² The figure contains a triangle. One side is 3.2 feet. A second side is 4.7 feet. The angle between the given sides is 62 degrees.

Respuesta :

We are given two sides and their included angle. Using the side-angle-side method we can find the Area of the triangle using the following formula:

Area = 0.5 ab sin(γ)

a = Measure of first side = 3.2 feet
b = Measure of second side = 4.7 feet
γ = Angle between the two sides = 62 degrees

Using the values in the above formula, we get:

Area = 0.5 x ( 3.2) x (4.7) x (sin(62))

Area = 6.64 square feet (rounded to nearest hundredth) 

Thus, the Area of the given triangle is 6.64 square feet

The area of a triangle is 6.6397 square ft.

Triangle

Triangle has three sides and three angles.

Given

In [tex]\Delta ABC[/tex]

Side AB = 3.2 ft.

Side AC = 4.7 ft.

Angle A = 62 degree

How to calculate the area of the triangle?

The area of a triangle is given by the formula

[tex]\rm Area\ of\ \Delta ABC = \dfrac{1}{2} * Base*Height[/tex]

Here

Base = 3.2

Heignt = 4.7sin62

Then

[tex]\rm Area\ of\ \Delta ABC = \dfrac{1}{2} * 3.2*4.7sin62^{o} \\\\ \rm Area\ of\ \Delta ABC = 6.6397[/tex]

Thus, the area of a triangle is 6.6397 square ft.

More about triangles link is given below.

https://brainly.com/question/25813512

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