The height of the Eiffel Tower is 1050 feet. From the top, the angle of depression to a soccer ball on the ground is 20 degrees. Find, to the nearest foot, the distance from the soccer ball to the base of the Eiffel Tower.

Respuesta :

Since the angle of depression from the Eiffel tower is congruent to the angle of elevation from the soccer ball, the angle of elevation from the soccer field is 20°

Now, we can use the trigonometric function tangent to find the distance from the soccer ball to the base of the Eiffel Tower:
[tex]tan( \alpha )= \frac{opposite.side}{adjacent.side} [/tex]
[tex]tan(20)= \frac{1050}{a} [/tex]
[tex]a= \frac{1050}{tan(20)} [/tex]
[tex]a=2884.85[/tex]

We can conclude that 
the distance from the soccer ball to the base of the Eiffel Tower is 2884.85 feet.
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