Qing attached a dog ramp to her bed, which allows her dog to easily climb onto the mattress. The ramp is 48 inches long. The base of the ramp is 40 inches from the base of the bed. How high off the ground is the top of the mattress? Enter your answer, rounded to the nearest tenth, in the box.

Using the formula a^2+b^2=c^2you can fill in the numbers so that a=height of mattress in inches,b=40 inches or distance from base of the bed and c=48 or length of the ramp. a^2+40^2=48^2a^2+1600=2304
So then it becomes2304-1600=a^2704=a^2 26.5+=aSo, The top of the mattress(after rounding) is 26.5 inches off the ground.

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yogeshkumar49685 yogeshkumar49685 · Answer 2 · 2022-07-31T05:48:31+02:00

If the ramp is 48 inches long, the base of the ramp is 40 inches from the base then mattress is 26.53 inches high off from the ground.

What is pythagoras theorem?

Pythagoras theorem says that in a right angled triangle the square of hypotenuse is equal to sum of squares of base and perpendicular of that triangle.

How to find height?

When we draw the given problem then we will get a right angled triangle in which the hypotenuse is equal to the length of ramp and base is the the measurement how far the ramp is from the mattress and we have to find the perpendicular which will be the height of mattress from ground.

Height=[tex]\sqrt{48^{2} -40^{2} }[/tex]

=[tex]\sqrt{2304-1600}[/tex]

=[tex]\sqrt{704}[/tex]

=26.53 inches

Hence if the ramp is 48 inches long, the base of the ramp is 40 inches from the base then mattress is 26.53 inches high off from the ground.

Learn more about pythagoras theorem at https://brainly.com/question/343682

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