Use the figures to complete the statements proving the converse of the Pythagorean theorem. Drag and drop a phrase, value, or equation into the box to correctly complete the proof. To prove the converse of the Pythagorean theorem, we must show that if △ABC has sides of a, b, and c such that a² + b² = c² , then △ABC is a right triangle. Define △DEF so that it is a right triangle with sides a, b, and hypotenuse x. By the Pythagorean theorem, a² + b² = x² . Since a² + b² = c² and a² + b² = x², it must be true that c² = x². Since sides of triangles are positive, then we can conclude that . Thus, the two triangles have congruent sides and are congruent. Finally, if △ABC is congruent to a right triangle, then it must also be a right triangle. Two right triangles with points labeled in capital letters and sides labeled in lower case letters. Pls help!

Pythagoras theorem to complete the converse by dragging the phase of the value or equation to correct the proof. Stated answer will be c = X

In the converse of the Pythagoras theorem, we must know that triangle ABC has sides as a, b, c, and their whole square are combined as a right-angled triangle.

The triangle DEF has a, b, c hypotenuse X thus the Pythagoras theorem a² + b² = x² is true.

As the sides of the triangle are positive they are congruent is given. Then it has to be the right triangle. The triangles points are labeled as capital letters and sides in lower cases.

The answer is thus c = x.

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