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A person standing at the top of a skyscraper would be approximately 0.39 mi high.
Use 3959 mi as the radius of the earth.

How far out on the earth's horizon could this person be seen?

56

1

3088

or 39 miles.

Respuesta :

It is 56 miles. If you want the exact calculation, it is 55.6. Hope this helps! 

It is given the person standing at the top of a skyscraper is approximately 0.39 mi high. We need to find how far out on the earth's horizon could this person be seen.The earth radius is given as 3959 mi .

The Earth can be considered as a sphere.The distance from the center of earth to the person on skyscraper =3959+0.39=3959.39 miles

From the top of the building, we extend a tangent which will intersect with the extended radius of the earth. We then have a 45-45-90o triangle We can use

Pythagorean theorem to find x that is how far the person can see.

x² = 3959.34² - 3959²

x = √(3959.34² - 3959²) miles

x=55.57

Or x= 56 miles the person can be seen.

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