The number of mole of aluminum chloride, AlCl₃ produced from the reaction is 1.3 mole.
We'll begin by writing the balanced equation for the reaction.
2Al + 6HCl → 2AlCl₃ + 3H₂
From the balanced equation above,
2 moles of Al reacted to produce 2 moles of AlCl₃.
With the above information, we can obtain the number of mole of AlCl₃ obtained by the reaction of 1.3 mole of Al.
From the balanced equation above,
2 moles of Al reacted to produce 2 moles of AlCl₃.
Therefore,
1.3 mole of Al will also react to produce 1.3 mole of AlCl₃.
Thus, the mole of AlCl₃ produced is 1.3 mole.
Complete question:
If 1.3 mole of aluminium reacts with excess HCl, how many moles of AlCl₃ are produced.
Learn more about stoichiometry: https://brainly.com/question/15858344
