Answer:
Option B. [tex]x =\frac{23.sin55}{sin85}[/tex] is the expression.
Step-by-step explanation:
In the given triangle ∠D = 85° and ∠F = 55°
DE = x and EF = 23
Therefore by sine rule
[tex]\frac{sinD}{EF}=\frac{sinF}{ED}[/tex]
By putting the given values in the formula we can get the value of x
[tex]\frac{sin 85}{23}=\frac{sin55}{x}[/tex]
[tex]x =\frac{23.sin55}{sin85}[/tex]
Therefore option B. [tex]x =\frac{23.sin55}{sin85}[/tex] is the answer.
