Greenrune113
Greenrune113
17-05-2018
Mathematics
contestada
QF Q1.) Solve the triangle.
Respuesta :
Asdfjkadfjkakjf
Asdfjkadfjkakjf
19-05-2018
C=180-A-B=180-69-40=71deg.
by sine rule
b/sinB=a/sinA
b=a/sinA*sinB
=15/sin(69)*sin(40)
= 10.33
c/sinC=a/sinA
c=a/sinA*sinC
=15/sin(69)*sin(71)
= 15.19
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