On the plane curve defined by the parametric equations below, what point corresponds to t= -1
x=2t-1
y=t^3

(2,1)
(1,2)
(-1,3)
(-3,-1)

The equation x=2t-1 represent the x-coordinate. To get the value of x, substitute t with -1.

That is: x = 2(-1) - 1
= -2-1
= -3
Likewise, the equation y=t∧-3 represent the y-coordinate. Substituting t with -1,

y = (-1)∧-3
= -1

The point that correspond to t=-1 is (-3,-1).

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probu651 probu651 · Answer 2 · 2019-05-27T22:14:33+02:00

probu651 probu651

27-05-2019

Answer: I just took the test and got 100%

1. C, the parameter is t and the curve contains the set of points (2cos(t), sin(t)

2. B, up to the left and then up to the right

3. D, (-3,-1)

Feel free to mark as brainliest (:

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On the plane curve defined by the parametric equations below, what point corresponds to t= -1 x=2t-1 y=t^3 (2,1) (1,2) (-1,3) (-3,-1)

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On the plane curve defined by the parametric equations below, what point corresponds to t= -1
x=2t-1
y=t^3

(2,1)
(1,2)
(-1,3)
(-3,-1)