the vertices of an isosceles triangle are (-10,1 ), B(-6, 3), and C(-4, 7)
What is the equation of the triangles line of symmetry?
y=-x-3
y=-x+3
y=x+3
y=x-3

Look at the picture.

[tex]D\left(\dfrac{-10+(-4)}{2};\ \dfrac{1+7}{2}\right)\to D\left(\dfrac{-14}{2};\ \dfrac{8}{2}\right)\to D(-7;\ 4)[/tex]

[tex]y=ax+b\\\\D(-7;\ 4);\ B(-6;\ 3)\\\\DB:\ \left\{\begin{array}{ccc}4=-7a+b\\3=-6a+b\end{array}\right\ |subtract\ both\ sides\\\\1=-a\to\ a=-1\\\\4=-7\cdot(-1)+b\\7+b=4\ \ \ |-7\\b=-3\\\\DB:y=-x-3[/tex]

Answer: y = -x - 3

Answer Link

y5fbhbdv4n y5fbhbdv4n · Answer 2 · 2021-06-21T15:21:45+02:00

y5fbhbdv4n y5fbhbdv4n

21-06-2021

Answer:y=-x-3

Step-by-step explanation:

Answer Link

the vertices of an isosceles triangle are (-10,1 ), B(-6, 3), and C(-4, 7) What is the equation of the triangles line of symmetry? y=-x-3 y=-x+3 y=x+3 y=x-3

Respuesta :

Otras preguntas

the vertices of an isosceles triangle are (-10,1 ), B(-6, 3), and C(-4, 7)
What is the equation of the triangles line of symmetry?
y=-x-3
y=-x+3
y=x+3
y=x-3