Respuesta :
Short Answer D
Remark
Thank you for trying to pose the question so clearly.
Givens
T = 71 times
5 being rolled = 11
Substitution and solution.
P(T) = 71/100
P(6) = 11/100
P(Both) = P(T) * P(6)
P(Both) = 71/100 * 11/100
P(both) = (71 * 11) / 10000
P(Both) = 781/10000
Remark
Thank you for trying to pose the question so clearly.
Givens
T = 71 times
5 being rolled = 11
Substitution and solution.
P(T) = 71/100
P(6) = 11/100
P(Both) = P(T) * P(6)
P(Both) = 71/100 * 11/100
P(both) = (71 * 11) / 10000
P(Both) = 781/10000
Answer:
[tex]\frac{781}{10000}[/tex]
Step-by-step explanation:
Given :
Number on the Cube Number of Times Rolled:
1 10
2 8
3 33
4 29
5 11
6 9
Heads Tails
29 71
Total number of times cube rolled = 100
Total number of coin rolled = 100
Number of times getting 5 on a cube = 11
Number of times getting tails = 71
Now probability of getting 5 on the number cube :
=[tex]\frac{\text{Number of times 5 occurred on a cube}}{\text{Number of times cube is rolled}}[/tex]
= [tex]\frac{11}{100}[/tex]
Probability of getting tails = [tex]\frac{\text{Number of times tails occurred on a coin}}{\text{Number of times coin is rolled}}[/tex]
= [tex]\frac{71}{100}[/tex]
Probability of rolling a 5 on the number cube and the coin landing on tails = [tex]\frac{11}{100} \times \frac{71}{100}[/tex]
= [tex]\frac{781}{10000}[/tex]
Thus the probability of rolling a 5 on the number cube and the coin landing on tails is [tex]\frac{781}{10000}[/tex]