Use the tabulated half-cell potentials to calculate ΔG for the following balanced redox reaction:
Pb²⁺(aq)+Cu(s)⇌Pb(s)+Cu²⁺(aq) Given: Cu²⁺(aq)+2 e−→Cu(s) (E=0.34 V) and Pb²⁺(aq)+2 e⁻→Pb(s) (E=−0.13 V)

a. 46 kJ

b. −41 kJ

c. −0.47 kJ

d. −21 kJ

e. 91 kJ